Cho hình vẽ biết \[Ax\parallel By\], \[\widehat {xAO} = 35^\circ ,\widehat {OBy} = 145^\circ \].

Hỏi số đo \[\widehat {AOB}\] bằng bao nhiêu độ?

d) \({\left( {\frac{1}{3}} \right)^{50}} \cdot {\left( { - 9} \right)^{25}} - \frac{2}{3}:4\)

\( = {\left[ {{{\left( {\frac{1}{3}} \right)}^2}} \right]^{25}} \cdot {\left( { - 9} \right)^{25}} - \frac{2}{3}:4\)

\( = {\left( {\frac{1}{9}} \right)^{25}} \cdot {\left( { - 9} \right)^{25}} - \frac{2}{3}:4\)

\( = \left[ {\frac{1}{{{9^{25}}}}.{{\left( { - 9} \right)}^{25}}} \right] - \frac{2}{3}:4\)

\( = {\left( {\frac{{ - 9}}{9}} \right)^{25}} - \frac{2}{3}.\frac{1}{4}\)

i) \(\frac{3}{5}:\left( {\frac{{ - 1}}{{15}} - \frac{1}{6}} \right) + \frac{3}{5}:\left( {\frac{{ - 1}}{3} - 1\frac{1}{{15}}} \right)\)

\( = \frac{3}{5}:\left( {\frac{{ - 1}}{{15}} - \frac{1}{6}} \right) + \frac{3}{5}:\left( {\frac{{ - 1}}{3} - \frac{{16}}{{15}}} \right)\)

\( = \frac{3}{5}:\frac{{ - 7}}{{30}} + \frac{3}{5}:\frac{{ - 7}}{5}\)

\( = \frac{3}{5}.\frac{{ - 30}}{7} + \frac{3}{5}.\frac{{ - 5}}{7}\)

\( = \frac{3}{5}.\left( {\frac{{ - 30}}{7} + \frac{{ - 5}}{7}} \right)\)