Tìm số nguyên x, biết: (5x + 1)² = 121

\({x^2} - 5x = 0\)

\(x.\left( {x - 5} \right) = 0\)

\( \Rightarrow x = 0\) hoặc \(x - 5 = 0\)

\[x.y{\rm{ }} = {\rm{ }} - 21\;\]     

Ta có:   \[ - 21\; = \left( { - 1} \right).21 = 1.\left( { - 21} \right) = \left( { - 3} \right).7 = 3.\left( { - 7} \right)\]

Vì \[x,y{\rm{ }} \in \mathbb{Z}\;\]và \[x.y{\rm{ }} = {\rm{ }} - 21\;\]

 Suy ra : \[\;\left( {x;y} \right) \in \left\{ {\left( { - 1;21} \right);\left( {21; - 1} \right):\left( {1; - 21} \right);\left( { - 21;1} \right);\left( { - 3;7} \right);\left( {7; - 3} \right);\left( {3; - 7} \right);\left( { - 7;3} \right)} \right\}\]