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Trả lời:
a) \[10{x^2}\left( {2x - y} \right) + 6xy\left( {y - 2x} \right)\]
\[ = 10{x^2}\left( {2x - y} \right) - 6xy\left( {2x - y} \right)\]
\[ = \left( {2x - y} \right)\left( {10{x^2} - 6xy} \right)\]
\[ = 2x\left( {2x - y} \right)\left( {5x - 3y} \right).\]
b) \[\frac{{{x^3}}}{8} - \frac{{{y^3}}}{{27}} + \frac{x}{2} - \frac{y}{3}\]
\( = \left( {\frac{{{x^3}}}{8} - \frac{{{y^3}}}{{27}}} \right) + \left( {\frac{x}{2} - \frac{y}{3}} \right)\)
\( = \left[ {{{\left( {\frac{x}{2}} \right)}^3} - {{\left( {\frac{y}{3}} \right)}^3}} \right] + \left( {\frac{x}{2} - \frac{y}{3}} \right)\)
\( = \left( {\frac{x}{2} - \frac{y}{3}} \right)\left[ {{{\left( {\frac{x}{2}} \right)}^2} + \frac{x}{2}.\frac{y}{3} + {{\left( {\frac{y}{3}} \right)}^2}} \right] + \left( {\frac{x}{2} - \frac{y}{3}} \right)\)
\( = \left( {\frac{x}{2} - \frac{y}{3}} \right).\left( {\frac{{{x^2}}}{4} + \frac{{xy}}{6} + \frac{{{y^2}}}{9} + 1} \right)\).c) \({x^3} + 27 + \left( {x + 3} \right)\left( {x - 9} \right)\)
\( = \left( {x + 3} \right)\left( {{x^2} - 3x + 9} \right) + \left( {x + 3} \right)\left( {x - 9} \right)\)
\( = \left( {x + 3} \right)\left( {{x^2} - 3x + 9 + x - 9} \right)\)
\( = \left( {x + 3} \right)\left( {{x^2} - 2x} \right)\)
\( = \left( {x + 3} \right)x\left( {x - 2} \right)\).Hot: 1000+ Đề thi giữa kì 1 file word cấu trúc mới 2025 Toán, Văn, Anh... lớp 1-12 (chỉ từ 60k). Tải ngay
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