Điền dấu >, <, = thích hợp vào chỗ chấm (1 điểm)

a) \(\frac{5}{6}\,\, + \,\,\frac{2}{3}\)........ \(\frac{3}{2}\,\, - \,\,\frac{1}{3}\)

b) \(\frac{2}{3}\,\, \times \,\,\frac{3}{7}\)........ \(\frac{4}{3}\,\,:\,\,\frac{7}{3}\)

a) \(\frac{5}{6} + \frac{2}{3}\) > \(\frac{3}{2} - \frac{1}{3}\)

b)  \(\frac{2}{3} \times \frac{3}{7}\) < \(\frac{4}{3}:\frac{7}{3}\)

Giải thích:

\(\frac{5}{6} + \frac{2}{3}\) =  \(\,\frac{3}{2} = \frac{9}{6}\)

\(\frac{3}{2} - \frac{1}{3}\) =  \(\frac{7}{6}\,\)

\(\frac{9}{6}\,\,\)> \(\frac{7}{6}\)

Vậy: \(\frac{5}{6} + \frac{2}{3}\) > \(\frac{3}{2} - \frac{1}{3}\)

Giải thích:

\(\frac{2}{3} \times \frac{3}{7}\) = \(\frac{2}{7}\,\,\)   

\(\frac{4}{3}:\frac{7}{3}\) = \(\frac{4}{7}\,\,\)

\(\frac{2}{7}\) < \(\frac{4}{7}\)\(\frac{4}{3}:\frac{7}{3}\)

 Vậy: \(\frac{2}{3} \times \frac{3}{7}\) < \(\frac{4}{3}:\frac{7}{3}\)