Công dụng của máy biến áp là 

\[\frac{{{N_1}}}{{{N_2}}} = \frac{{{U_1}}}{{{U_2}}} \Rightarrow \frac{{{N_1}}}{{{U_1}}} = \frac{{{N_2}}}{{{U_2}}}\] (1)

\[\frac{{{N_1}}}{{{N_2} + 0,2{N_2}}} = \frac{{{U_1}}}{{{U_2} + 6}} \Rightarrow \frac{{{N_1}}}{{{U_1}}} = \frac{{1,2{N_2}}}{{{U_2} + 6}}\] (2)

Từ (1) và (2) có: \[{U_2} + 6 = 1,2{U_2} \Rightarrow {U_2} = 30\,V.\] Chọn A.

Ta có: \(\frac{{{N_1}}}{{{N_2}}} = \frac{{{U_1}}}{{{U_2}}} \Rightarrow \frac{{{N_1}}}{{{N_2}}} = \frac{{{U_1}}}{{50}}(1) \Rightarrow \left\{ {\begin{array}{*{20}{l}}{ \cdot {\rm{ Khi giam n v\`o ng: }}\frac{{{N_1}}}{{{N_2} - n}} = \frac{{{U_1}}}{U}}\\{ \cdot {\rm{ Khi tang n v\`o ng: }}\frac{{{N_1}}}{{{N_2} + {\rm{n}}}} = \frac{{{U_1}}}{{2U}}}\end{array} \Rightarrow {N_2} = 3n} \right.\)

Khi tăng thêm 3 n vòng \( \Rightarrow \frac{{{{\rm{N}}_1}}}{{\;{{\rm{N}}_2} + 3{\rm{n}}}} = \frac{{{{\rm{U}}_1}}}{{{{\rm{U}}_2}}} \Rightarrow \frac{1}{2}\left( {\frac{{{{\rm{N}}_1}}}{{\;{{\rm{N}}_2}}}} \right) = \frac{{{{\rm{U}}_1}}}{{{{\rm{U}}_2}}}\) (3)

Thay (1) vào (3) ta có: \(\frac{1}{2}\left( {\frac{{{{\rm{U}}_1}}}{{50}}} \right) = \frac{{{{\rm{U}}_1}}}{{{{\rm{U}}_2}}} \Rightarrow {{\rm{U}}_2} = 100\;{\rm{V}}\)

Đáp án: 100 V.