Nguyên hàm của \(\int {\left( {{x^2} - 3x + \frac{1}{x}} \right)} dx\) là

A. \({f_1}\left( x \right) = \frac{1}{{3\sqrt[3]{{{x^2}}}}} + \frac{1}{{\sqrt x }} + \frac{3}{2}\sqrt x \);

B. \({f_2}\left( x \right) = \frac{1}{{3\sqrt[3]{{{x^2}}}}} + \frac{1}{{\sqrt x }} + \frac{3}{{2\sqrt x }}\);

C. \({f_3}\left( x \right) = \frac{{\sqrt[3]{{{x^2}}}}}{3} + \frac{1}{{\sqrt x }} + \frac{3}{2}\sqrt x \);

D. \({f_4}\left( x \right) = \frac{1}{{3\sqrt[3]{{{x^2}}}}} + \frac{1}{2}\sqrt x + \frac{3}{{2\sqrt x }}\).

A. F(x) = x⁵ – 2x⁴ – 3x² + C;

B. F(x) = x⁵ – x⁴ – x² + C;

C. F(x) = x⁵ – 4x⁴ – 2x² + C;

D. F(x) = x⁵ + 2x⁴ – 3x² + C.

A. \(F\left( x \right) = \frac{1}{3}{x^3} + \frac{3}{2}{x^2} + 2x + C\);

B. \(F\left( x \right) = \frac{1}{3}{x^3} + \frac{2}{3}{x^2} + 2x + C\);

C. F(x) = 2x + 3 + C;

D. \(F\left( x \right) = \frac{1}{3}{x^3} - \frac{2}{3}{x^2} + 2x + C\).

A. \( - \frac{1}{3}\ln \left| {3x + 1} \right| + C\);

B. \(\frac{1}{3}\ln \left| {3x + 1} \right| + C\);

C. \(\frac{1}{3}\ln \left| {3x - 1} \right| + C\);

D. \( - \frac{1}{3}{\left( {3x + 1} \right)^{\frac{2}{3}}} + C\).

A. 3x² + 1 + C;

B. \(\frac{1}{4}{x^4} + \frac{1}{2}{x^2} + C\);

C. x³ + x + C;

D. x⁴ + x² + C.

A. 2x + C;

B. \(\frac{1}{3}{x^3} + C\);

C. x³ + C;

D. 3x³ + C.