Tính \[{f^{\left( {2018} \right)}}\left( 2 \right)\] của hàm số \[f\left( x \right) = \ln \left( {x - 1} \right)\]?

A. S = 2

B. S = 3

C. S = 1

D. S = 0

A. I = 2

B. I = 1

C. \[I = \frac{1}{2}\]

D. I = 0

A. \[\frac{{20}}{\pi }cm\]

B. \[\frac{{10}}{\pi }cm\]

C. \[\frac{{30}}{{{\pi ^2}}}cm\]

D. 20 cm

A. Q = 50

B. Q = 49

C. Q = 52

D. cả A, B, C đều sai

A. \[\frac{1}{{2\pi }}\left( {0,16} \right){m^3}/s\]

B. \[\frac{1}{{2\pi }}\left( {0,16} \right)m/s\]

C. \[\frac{1}{{2\pi }}\left( {0,08} \right)m/s\]

D. \[\frac{1}{{2\pi }}\left( {0,08} \right){m^3}/s\]

A. \[f\left( x \right) = 1 - \frac{1}{3}\left( {x - 1} \right) - \frac{2}{9}{\left( {x - 1} \right)^2} + o\left( {{{\left( {x - 1} \right)}^2}} \right)\]

B. \[f\left( x \right) = 1 + \frac{1}{3}\left( {x - 1} \right) - \frac{2}{9}{\left( {x - 1} \right)^2} + o\left( {{{\left( {x - 1} \right)}^2}} \right)\]

C. \[f\left( x \right) = 1 - \frac{1}{3}\left( {x - 1} \right) + \frac{2}{9}{\left( {x - 1} \right)^2} + o\left( {{{\left( {x - 1} \right)}^2}} \right)\]

D. \[f\left( x \right) = 1 - \frac{1}{3}\left( {x - 1} \right) + \frac{4}{9}{\left( {x - 1} \right)^2} + o\left( {{{\left( {x - 1} \right)}^2}} \right)\]