Tìm \(x\), biết:

b) \(\frac{2}{3} - 1\frac{4}{{15}}x = \frac{{ - 3}}{5}\);

e) \(\frac{{15}}{{37}} \cdot \left( {\frac{{38}}{{41}} - \frac{{74}}{{45}}} \right) - \frac{{38}}{{41}} \cdot \left( {\frac{{15}}{{37}} + \frac{{82}}{{76}}} \right)\)

\( = \frac{{15}}{{37}} \cdot \frac{{38}}{{41}} - \frac{{15}}{{37}} \cdot \frac{{74}}{{45}} - \frac{{38}}{{41}} \cdot \frac{{15}}{{37}} - \frac{{38}}{{41}} \cdot \frac{{82}}{{76}}\)

\[ = \left( {\frac{{15}}{{37}} \cdot \frac{{38}}{{41}} - \frac{{38}}{{41}} \cdot \frac{{15}}{{37}}} \right) + \left( { - \frac{{15}}{{37}} \cdot \frac{{74}}{{45}} - \frac{{38}}{{41}} \cdot \frac{{82}}{{76}}} \right)\]

\[ = 0 + \left( { - \frac{1}{1} \cdot \frac{2}{3} - \frac{{38}}{{41}} \cdot \frac{{41 \cdot 2}}{{38 \cdot 2}}} \right)\]

i) \({\left( {x - \frac{2}{9}} \right)^3} = {\left( {\frac{2}{3}} \right)^6}\)

\({\left( {x - \frac{2}{9}} \right)^3} = {\left( {\frac{4}{9}} \right)^3}\)

\(x - \frac{2}{9} = \frac{4}{9}\)

\(x = \frac{6}{9}\)

\(x = \frac{2}{3}\)