Tính:

c) log₈16 – log₈2;

d) log₂6 ∙ log₆8.

Question

c) log₈16 – log₈2 = $\log_{8} \frac{16}{2} = \log_{8} 8 = 1$ .

d) log₂6 ∙ log₆8 = $\log_{2} 6 \cdot \frac{\log_{2} 8}{\log_{2} 6} = \log_{2} 8 = \log_{2} 2^{3} = 3$ .

Answer 1

Trả lời:

Giải bởi Vietjack

c) log₈16 – log₈2 = $\log_{8} \frac{16}{2} = \log_{8} 8 = 1$ .

d) log₂6 ∙ log₆8 = $\log_{2} 6 \cdot \frac{\log_{2} 8}{\log_{2} 6} = \log_{2} 8 = \log_{2} 2^{3} = 3$ .

Tính: c) log816 – log82; d) log26 ∙ log68.