Tính tích phân\[\mathop \smallint \limits_0^{\ln 3} \frac{{{\rm{dx}}}}{{\sqrt {{{\rm{e}}^{\rm{x}}}{\rm{ + 1}}} }}\]

A. \[\mathop \smallint \limits_{ - {\rm{a}}}^{\rm{a}} {\rm{f(x)dx}} = 2\mathop \smallint \limits_0^{\rm{a}} {\rm{f(x)dx}}\]

B. \[\mathop \smallint \limits_{ - {\rm{a}}}^{\rm{a}} {\rm{f(x)dx}} = - \mathop \smallint \limits_0^{\rm{a}} {\rm{f(x)dx}}\]

C. \[\mathop \smallint \limits_{ - {\rm{a}}}^{\rm{a}} {\rm{f(x)dx}} = \mathop \smallint \limits_0^{\rm{a}} {\rm{f(x)dx}}\]

D. \[\mathop \smallint \limits_{ - {\rm{a}}}^{\rm{a}} {\rm{f(x)dx}} = 2\mathop \smallint \limits_{ - a/2}^{{\rm{a/2}}} {\rm{f(x)dx}}\]

A. f'(0) = 0

B. f'(0) = -1

C. f'(0) = 1

D. Không tồn tại

A. \[\frac{1}{5}\]

B. 0

C. \(\infty \)

D. \[\frac{1}{{10}}\]

A. \[\left( {\forall {\rm{x}} \in \left[ {{\rm{a,b}}} \right]} \right){\rm{f(x)}} < {\rm{g(x)}} \Rightarrow \mathop \smallint \limits_{\rm{a}}^{\rm{b}} {\rm{f(x)dx}} > \mathop \smallint \limits_{\rm{a}}^{\rm{b}} {\rm{g(x)dx}}\]

B. \[\left( {\forall {\rm{x}} \in \left[ {{\rm{a,b}}} \right]} \right){\rm{f(x)}} \le {\rm{g(x)}} \Rightarrow \mathop \smallint \limits_{\rm{a}}^{\rm{b}} {\rm{f(x)dx}} \le \mathop \smallint \limits_{\rm{a}}^{\rm{b}} {\rm{g(x)dx}}\]

C. \[\left( {\forall {\rm{x}} \in \left[ {{\rm{a,b}}} \right]} \right){\rm{f(x)}} \le {\rm{g(x)}} \Rightarrow \mathop \smallint \limits_{\rm{a}}^{\rm{b}} {\rm{f(x)g(x)dx}} \le \mathop \smallint \limits_{\rm{a}}^{\rm{b}} {\rm{g(x)dx}}\]

D. \[{\rm{f(x)}} \le {\rm{g(x)}} \Rightarrow \mathop \smallint \limits_{\rm{a}}^{\rm{b}} {\rm{g(x)dx}} \le \mathop \smallint \limits_{\rm{a}}^{\rm{b}} {\rm{g(x)dx}}\]

A. \[\frac{{({\rm{n}} - 1)!}}{{{{\rm{x}}^{\rm{n}}}}}\]

B. Kết quả khác

C. \[{( - 1)^{{\rm{n}} - 1}}.\frac{{({\rm{n}} - 1)!}}{{{{\rm{x}}^{\rm{n}}}}}\]

D. \[{{\rm{a}}^{{\rm{n}} - 1}}.{{\rm{e}}^{{\rm{ax}}}}\]

A. 0

B. -1/80

C. 10

D. 20