Tìm vi phân của các hàm số \(y = \sin 2x + {\sin ^3}x\)

A. \(dy = (1 + {\tan ^2}2x)dx\)

B. \(dy = (1 - {\tan ^2}2x)dx\)

C. \(dy = 2(1 - {\tan ^2}2x)dx\)

D. \(dy = 2(1 + {\tan ^2}2x)dx\)

A. \(dy = \frac{1}{{\sqrt[3]{{{{(x + 1)}^2}}}}}dx\)

B. \(dy = \frac{3}{{\sqrt[3]{{{{(x + 1)}^2}}}}}dx\)

C. \(dy = \frac{2}{{\sqrt[3]{{{{(x + 1)}^2}}}}}dx\)

D. \(dy = \frac{1}{{3\sqrt[3]{{{{(x + 1)}^2}}}}}dx\)

A. \({\rm{d}}y = \left( { - \cos x + 3\sin x} \right){\rm{d}}x\).

B. \({\rm{d}}y = \left( { - \cos x - 3\sin x} \right){\rm{d}}x\).

C. \({\rm{d}}y = \left( {\cos x + 3\sin x} \right){\rm{d}}x\).

D. \({\rm{d}}y = - \left( {\cos x + 3\sin x} \right){\rm{d}}x\).

A. .$dy=2(x-1)dx$

B.$dy=2(x-1)$

C.$dy=(x-1)dx$

D.$dy={(x-1)}^{2}dx$

A. $dy=\frac{1}{7}dx$

B.$dy=7dx$

C. $dy=\frac{-1}{7}dx$

D. $dy=-7dx$

A. \({\rm{d}}y = \frac{{{\rm{d}}x}}{{{{\left( {x - 1} \right)}^2}}}\).

B. \({\rm{d}}y = \frac{{3{\rm{d}}x}}{{{{\left( {x - 1} \right)}^2}}}\).

C. \({\rm{d}}y = \frac{{ - 3{\rm{d}}x}}{{{{\left( {x - 1} \right)}^2}}}\).

D. \({\rm{d}}y = - \frac{{{\rm{d}}x}}{{{{\left( {x - 1} \right)}^2}}}\).