Viết các số đo sau dưới dạng số đo có đơn vị là dam²

\(2{\rm{da}}{{\rm{m}}^2}16{{\rm{m}}^2}\)                            \(8{\rm{da}}{{\rm{m}}^2}62{{\rm{m}}^2}\)                             \(52{\rm{da}}{{\rm{m}}^2}40{{\rm{m}}^2}\)

\(46{\rm{da}}{{\rm{m}}^2}5{{\rm{m}}^2}\)                            \(16{\rm{da}}{{\rm{m}}^2}29{{\rm{m}}^2}\)                \(32{\rm{da}}{{\rm{m}}^2}9{{\rm{m}}^2}\)

\(3{\rm{k}}{{\rm{m}}^2}4{\rm{c}}{{\rm{m}}^2}\)                             \(13{\rm{ h}}{{\rm{m}}^2}24{\rm{d}}{{\rm{m}}^2}\)

Hướng Dẫn Giải

- \(2{\rm{da}}{{\rm{m}}^2}16{{\rm{m}}^2} = 2{\rm{da}}{{\rm{m}}^2} + 16{{\rm{m}}^2} = 2{\rm{da}}{{\rm{m}}^2} + 16:100{\rm{da}}{{\rm{m}}^2}\)

\( = 2{\rm{da}}{{\rm{m}}^2} + 0,16{\rm{da}}{{\rm{m}}^2} = 2,16{\rm{da}}{{\rm{m}}^2}\)

Vậy \(2{\rm{da}}{{\rm{m}}^2}16{{\rm{m}}^2} = 2,16{\rm{da}}{{\rm{m}}^2}\)

Tương tự có:

- \(8{\rm{da}}{{\rm{m}}^2}62{{\rm{m}}^2} = 8,62{\rm{da}}{{\rm{m}}^2}\)

- \(52{\rm{da}}{{\rm{m}}^2}40{{\rm{m}}^2} = 52,4{\rm{da}}{{\rm{m}}^2}\)

- \(46{\rm{da}}{{\rm{m}}^2}5{{\rm{m}}^2} = 46,05{\rm{da}}{{\rm{m}}^2}\)

- \(16{\rm{da}}{{\rm{m}}^2}29{{\rm{m}}^2} = 16,29{\rm{da}}{{\rm{m}}^2}\)

- \(32{\rm{da}}{{\rm{m}}^2}9{{\rm{m}}^2} = 32,09{\rm{da}}{{\rm{m}}^2}\)

- \(3{\rm{k}}{{\rm{m}}^2}4{\rm{c}}{{\rm{m}}^2} = 3{\rm{k}}{{\rm{m}}^2} + 4{\rm{c}}{{\rm{m}}^2} = 3 \times 10000{\rm{da}}{{\rm{m}}^2} + 4:1000000{\rm{da}}{{\rm{m}}^2}\)

\( = 30000{\rm{da}}{{\rm{m}}^2} + 0,000004{\rm{da}}{{\rm{m}}^2} = 30000,000004{\rm{da}}{{\rm{m}}^2}\)

- \(13{\rm{ h}}{{\rm{m}}^2}24{\rm{d}}{{\rm{m}}^2} = 13 \times 100{\rm{da}}{{\rm{m}}^2} + 24:10000{\rm{da}}{{\rm{m}}^2}\)

\( = 1300{\rm{da}}{{\rm{m}}^2} + 0,0024{\rm{da}}{{\rm{m}}^2} = 1300,0024{\rm{da}}{{\rm{m}}^2}\).