PHẦN II. TỰ LUẬN (8,0 điểm)

(1,5 điểm) Tính giá trị của các biểu thức sau (tính hợp lí nếu có thể):

a) \[\frac{5}{7} - \frac{4}{7}.\frac{1}{6}\];                                                           

b) \(\left( {\frac{{ - 7}}{4} + \frac{7}{{13}}} \right):\frac{4}{5} + \left( {\frac{6}{{13}} - \frac{1}{4}} \right):\frac{4}{5}\);      

c) \(\sqrt {\frac{4}{{25}}} + \left| { - \frac{4}{5}} \right| - \frac{9}{5}.{\left( {\frac{{ - 1}}{3}} \right)^2} - 0,75\).

a) \[\frac{5}{7} - \frac{4}{7}.\frac{1}{6} = \frac{5}{7} - \frac{2}{{21}} = \frac{{15}}{{21}} - \frac{2}{{21}} = \frac{{13}}{{21}}\].

b) \(\left( {\frac{{ - 7}}{4} + \frac{7}{{13}}} \right):\frac{4}{5} + \left( {\frac{6}{{13}} - \frac{1}{4}} \right):\frac{4}{5}\)

\( = \left( {\frac{{ - 7}}{4} + \frac{7}{{13}}} \right).\frac{5}{4} + \left( {\frac{6}{{13}} - \frac{1}{4}} \right).\frac{5}{4}\)

\( = \frac{5}{4}.\left( {\frac{{ - 7}}{4} + \frac{7}{{13}} + \frac{6}{{13}} - \frac{1}{4}} \right)\)\( = \frac{5}{4}.\left( {\frac{{ - 8}}{4} + \frac{{13}}{{13}}} \right)\)

\( = \frac{5}{4}.\left( { - 2 + 1} \right) = \frac{5}{4}.\left( { - 1} \right) = - \frac{5}{4}\).

c) \(\sqrt {\frac{4}{{25}}} + \left| { - \frac{4}{5}} \right| - \frac{9}{5}.{\left( {\frac{{ - 1}}{3}} \right)^2} - 0,75\)

\( = \frac{2}{5} + \frac{4}{5} - \frac{9}{5}.\frac{1}{9} - \frac{3}{4}\)

\( = \frac{2}{5} + \frac{4}{5} - \frac{1}{5} - \frac{3}{4}\)

\( = \frac{5}{5} - \frac{3}{4} = 1 - \frac{3}{4} = \frac{1}{4}\).