Tính giá trị của biểu thức

a) 25 489 + 9 024 – 10 365	g) 312,56 + 105,78 – 68,124
b) 2 348 × 48 – 6 245	h) 30,56 × 2,5 + 4,98
c) 60 250 : 5 + 15 423 – 5 797	i) 360,57 : 3 – 59,209
d) \[\frac{3}{5} + \frac{1}{2} + \frac{7}{{10}}\]	j) \[\frac{7}{4} - \frac{2}{5} - \frac{3}{{20}}\]
e) \[\frac{3}{5} \times \frac{1}{2} + \frac{5}{2} \times \frac{3}{5} + \frac{4}{2} \times \frac{3}{5}\]	k) \[\frac{3}{2}:\frac{5}{2} + \frac{3}{2}:\frac{{10}}{7}\]
f) 4 × 50 × 125 × 2 × 8	l) 3,5 : 0,5 + 12,46 : 0,125 + 4,3 : 0,2

a) 25 489 + 9 024 – 10 365

= 34 513 – 10 365

= 24 148

g) 312,56 + 105,78 – 68,124

= 418,34 – 68,124

= 350,216

b) 2 348 × 48 – 6 245

= 112 704 – 6 245

= 106 459

h) 30,56 × 2,5 + 4,98

= 76,4 + 4,98

= 81,38

c) 60 250 : 5 + 15 423 – 5 797

= 12 050 + 15 423 – 5 797

= 27 473 – 5 797

= 21 676

i) 360,57 : 3 – 59,209

= 120,19 – 59,209

= 60,981

d) \[\frac{3}{5} + \frac{1}{2} + \frac{7}{{10}}\]

\[ = \frac{6}{{10}} + \frac{5}{{10}} + \frac{7}{{10}}\]

\[ = \frac{{18}}{{10}} = \frac{9}{5}\]

j) \[\frac{7}{4} - \frac{2}{5} - \frac{3}{{20}}\]

\[ = \frac{{35}}{{20}} - \frac{8}{{20}} - \frac{3}{{20}}\]

\[ = \frac{{24}}{{20}} = \frac{6}{5}\]

e) \[\frac{3}{5} \times \frac{1}{2} + \frac{5}{2} \times \frac{3}{5} + \frac{4}{2} \times \frac{3}{5}\]

\[ = \frac{3}{5} \times \left( {\frac{1}{2} + \frac{5}{2} + 2} \right)\]

\[ = \frac{3}{5} \times \left( {\frac{1}{2} + \frac{5}{2} + \frac{4}{2}} \right)\]

\[ = \frac{3}{5} \times \frac{{10}}{2}\]

= 3

k) \[\frac{3}{2}:\frac{5}{2} + \frac{3}{2}:\frac{{10}}{7}\]

\[ = \frac{3}{2} \times \frac{2}{5} + \frac{3}{2} \times \frac{7}{{10}}\]

\[ = \frac{3}{2} \times \left( {\frac{2}{5} + \frac{7}{{10}}} \right)\]

\[ = \frac{3}{2} \times \left( {\frac{4}{{10}} + \frac{7}{{10}}} \right)\]

\[ = \frac{3}{2} \times \frac{{11}}{{10}}\]

\[ = \frac{{33}}{{20}}\]

f) 4 × 50 × 125 × 2 × 8

= (125 × 8) × (50 × 2) × 4

= 1 000 × 100 × 4

= 400 000

l) 3,5 : 0,5 + 12,46 : 0,125 + 4,3 : 0,2

= 3,5 × 2 + 12,46 × 8 + 4,3 × 5

= 7 + 99,68 + 21,5

= 106,68 + 21,5

= 128,18