Cho glycerol dư vào ống nghiệm chứa $\text{C}\text{u}(\text{O}\text{H}){}_2$. Hiện tượng quan sát được là

HC\equiv C-C{H}_3.

C{H}_3-C\equiv C-C{H}_3.

C{H}_2=CH-C{H}_2-C{H}_3.

C{H}_2=CH-C\equiv CH.

$\text{O}{}_2$.

$\text{C}\text{O}{}_2$.

$\text{C}\text{H}{}_4$.

$\text{N}\text{H}{}_3$.

2.

4.

5.

3.

$\text{C}\text{l}-\text{C}\text{H}{}_2-\text{C}\text{O}\text{O}\text{H}$.

$\text{C}{}_6\text{H}{}_5-\text{C}\text{H}{}_2-\text{C}\text{l}$.

$\text{C}\text{H}{}_3-\text{C}\text{H}{}_2-\text{M}\text{g}-\text{B}\text{r}$.

$\text{C}\text{H}{}_3-\text{C}\text{O}-\text{C}\text{l}$.

$\text{C}{}_n\text{H}{}_{2\text{n}+6}(\text{n}\ge 6)$.

$\text{C}{}_{\text{n}}\text{H}{}_{2\text{n}-6}(\text{n}\ge 3)$.

$\text{C}{}_{\text{n}}\text{H}{}_{2n-8}(n\ge 8)$.

$\text{C}{}_n\text{H}{}_{2\text{n}\text{-}6}(\text{n}\ge 6)$.

$\text{C}{}_2\text{H}{}_4$.

$\text{C}{}_3\text{H}{}_8$.

$\text{C}{}_2\text{H}{}_6$.

$\text{C}{}_3\text{H}{}_4$.