Điền dấu thích hợp vào chỗ chấm: \(\frac{2}{3}\sqrt[3]{{18}}.....\frac{3}{4}\sqrt[3]{{12}}\).

Đáp án đúng là: A

Ta có: \(\frac{2}{3}\sqrt[3]{{18}} = \sqrt[3]{{18.{{\left( {\frac{2}{3}} \right)}^3}}} = \sqrt[3]{{18.\frac{8}{{27}}}} = \sqrt[3]{{\frac{{16}}{3}}} = \sqrt[3]{{5\frac{1}{3}}}\).

\(\frac{3}{4}\sqrt[3]{{12}} = \sqrt[3]{{12.{{\left( {\frac{3}{4}} \right)}^3}}} = \sqrt[3]{{12.\frac{{27}}{{64}}}} = \sqrt[3]{{\frac{{81}}{{16}}}} = \sqrt[3]{{5\frac{1}{{16}}}}\).

Ta có: \(5\frac{1}{3} > 5\frac{1}{{16}}\) nên \(\frac{2}{3}\sqrt[3]{{18}} > \frac{3}{4}\sqrt[3]{{12}}\).