B. TỰ LUẬN (3,0 điểm)

Câu 25-27. (1,5 điểm) Cho hai đa thức: \(P\left( x \right) = 3{x^5} + 5{x^3} - x - 9,\)

                                                        \(K\left( x \right) = 7{x^5} + x - 3{x^2} - 8{x^3} - 4{x^5} + 3{x^2} + 5 + 5{x^3}\).

a) Thu gọn đa thức \(K\left( x \right)\). Tính \(K\left( 1 \right)\).

b) Ta có: \(P\left( x \right) - K\left( x \right) = 3{x^5} + 5{x^3} - x - 9 - \left( {3{x^5} - 3{x^3} + x + 5} \right)\)

                                     \( = \left( {3{x^5} - 3{x^5}} \right) + \left( {5{x^3} - 3{x^3}} \right) - 2x - 14\)

                                     \( = 2{x^3} - 2x - 14\).

c) Ta có: \(H\left( x \right) + 2K\left( x \right) = P\left( x \right)\) hay \(H\left( x \right) = P\left( x \right) - 2K\left( x \right)\).

Do đó, \(H\left( x \right) = 3{x^5} + 5{x^3} - x - 9 - 2\left( {3{x^5} - 3{x^3} + x + 5} \right)\)

           \(H\left( x \right) = 3{x^5} + 5{x^3} - x - 9 - 6{x^5} + 6{x^3} - 2x - 10\)

          \(H\left( x \right) = \left( {3{x^5} - 6{x^5}} \right) + \left( {5{x^3} + 6{x^3}} \right) + \left( { - x - 2x} \right) + \left( { - 9 - 10} \right)\)

         \(H\left( x \right) = - 3{x^5} + 11{x^3} - 3x - 19\).

Vậy \(H\left( x \right) = - 3{x^5} + 11{x^3} - 3x - 19\).