Tìm λ để hệ véc tơ sau phụ thuộc tuyến tính: \[{\rm{u}} = ({\rm{\lambda }},\frac{{ - 1}}{2},\frac{{ - 1}}{2}),{\rm{v}} = (\frac{{ - 1}}{2},{\rm{\lambda }},\frac{{ - 1}}{2}),{\rm{w}} = (\frac{{ - 1}}{2},\frac{{ - 1}}{2},{\rm{\lambda }})\]

A. \[{\rm{\lambda }} = 10\]

B. \[{\rm{\lambda }} = - 11\]

C. \[{\rm{\lambda }} = 12\]

D. \[{\rm{\lambda }} = 11\]

A. \[{\rm{u}} = (6,12,18,24)\]

B. \[{\rm{u}} = (7, - 2,3,0)\]

C. \[{\rm{u}} = (1,2,3,4)\]

D. \[{\rm{u}} = ( - 2,3,7,0)\]

A. \[{{\rm{x}}_1} = 2,{{\rm{x}}_2} = 1,{{\rm{x}}_3} = 2,{{\rm{x}}_4} = 1\]

B. \[{{\rm{x}}_1} = - 3,{{\rm{x}}_2} = 1,{{\rm{x}}_3} = 2,{{\rm{x}}_4} = - 1\]

C. \[{{\rm{x}}_1} = - 3,{{\rm{x}}_2} = - 1,{{\rm{x}}_3} = 2,{{\rm{x}}_4} = - 1\]

D. \[{{\rm{x}}_1} = 4,{{\rm{x}}_2} = - 5,{{\rm{x}}_3} = 7,{{\rm{x}}_4} = 3\]

A. \[{\rm{u}} = (1, - 2,1),{\rm{v}} = (2,1, - 1),{\rm{w}} = (7, - 1,4)\]

B. \[{\rm{u}} = (1, - 3,7),{\rm{v}} = (2,0,8),{\rm{w}} = (8, - 1,8),{\rm{x}}(3, - 9,7)\]

C. \[{\rm{u}} = (1,2, - 3),{\rm{v}} = (1, - 3,2),{\rm{w}} = (2, - 1,5)\]

D. \[{\rm{u}} = (2, - 3,13),{\rm{v}} = (0,0,0),{\rm{w}} = (1, - 10,11)\]

A. \(\left\{ {\begin{array}{*{20}{c}}{(x,y,z) + (x\prime ,y\prime ,x\prime ) = (x + x\prime ,y + y\prime ,z + z\prime }\\{\alpha (x,y,z) = (\alpha x,y,z);\alpha \in R}\end{array}} \right.\)

B. \(\left\{ {\begin{array}{*{20}{c}}{(x,y,z) + (x\prime ,y\prime ,x\prime ) = (x + x\prime ,y + y\prime ,z + z\prime )}\\{\alpha (x,y,z) = (2\alpha x,2\alpha y,2\alpha z);\alpha \in R}\end{array}} \right.\)

C. \(\left\{ {\begin{array}{*{20}{c}}{(x,y,z) + (x\prime ,y\prime ,x\prime ) = (x + x\prime + 1,y + y\prime + 1,z + z\prime + 1)}\\{\alpha (x,y,z) = (0,0,0);\alpha \in R}\end{array}} \right.\)

D. \(\left\{ {\begin{array}{*{20}{c}}{(x,y,z) + (x\prime ,y\prime ,x\prime ) = (x + x\prime ,y + y\prime ,z + z\prime )}\\{\alpha (x,y,z) = (\alpha x,\alpha y,\alpha z);\alpha \in R}\end{array}} \right.\)

A. Các véc tơ (x, y, z) thoả mãn\[{\rm{x}} \le {\rm{y}} \le {\rm{z}}\]

B. Các véc tơ (x, y, z) thoả mãn x + y + z = 0

C. Các véc tơ (x, y, z) thoả mãn xy = 0

D. Các véc tơ (x, y, z) thoả mãn 3x + 2y - 4z = 0