Thực hiện phép tính , 

a) \[1\frac{2}{5} + 3\frac{3}{5}.\]          b) \[\left( {\frac{{ - 5}}{9}} \right) \cdot \frac{3}{{11}} + \left( {\frac{{ - 4}}{9}} \right) \cdot \frac{3}{{11}}.\]

c) \({\rm{2023}}--{\left( {\frac{{\rm{1}}}{{\rm{3}}}} \right)^{\rm{2}}} \cdot {{\rm{3}}^{{\rm{ 2}}}}.\)                                  d) \(\frac{{{5^{16}} \cdot {{27}^7}}}{{{{125}^5} \cdot {9^{11}}}}.\)

a) \[1\frac{2}{5} + 3\frac{3}{5} = \frac{7}{5} + \frac{{18}}{5}\]

\[ = \frac{{25}}{5} = 5.\]                                             

b) \[\left( {\frac{{ - 5}}{9}} \right).\frac{3}{{11}} + \left( {\frac{{ - 4}}{9}} \right).\frac{3}{{11}}\]

\[ = \frac{3}{{11}}.\left[ {\left( {\frac{{ - 5}}{9}} \right) + \left( {\frac{{ - 4}}{9}} \right)} \right]\]

\[ = \frac{3}{{11}}.\left( { - 1} \right) = \frac{{ - 3}}{{11}}.\]

c) \[2023 - {\left( {\frac{1}{3}} \right)^2}{.3^2}\]

\[ = 2023 - \frac{1}{9}.9\]

\[ = 2023 - 1 = 2022.\]

d) \(\frac{{{5^{16}}{{.27}^7}}}{{{{125}^5}{{.9}^{11}}}} = \frac{{{5^{16}}.{{\left( {{3^3}} \right)}^7}}}{{{{\left( {{5^3}} \right)}^5}.{{\left( {{3^2}} \right)}^{11}}}}\) 

\( = \frac{{{5^{16}}{{.3}^{21}}}}{{{5^{15}}{{.3}^{22}}}} = \frac{5}{3}\)