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Câu hỏi:

02/06/2026 50 Lưu

Điền dấu >, <, = thích hợp vào chỗ chấm

\(\frac{4}{5}\,\, + \,\,\frac{1}{{10}}\) ……… \(\frac{1}{2}\)

\(\frac{5}{8}\,\, \times \,\,\frac{2}{5}\) ……… \(\frac{3}{4}\)

\(\frac{1}{2}\,\, - \,\,\frac{1}{4}\) ……… \(\frac{1}{4}\)

\(\frac{3}{4}\,\,:\,\,\frac{6}{9}\,\, - \,\,\frac{1}{2}\) ……… \(\frac{7}{8}\)

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Trả lời:

verified Giải bởi Vietjack

\(\frac{4}{5}\,\, + \,\,\frac{1}{{10}}\) >  \(\frac{1}{2}\)                                                  \(\frac{5}{8}\,\, \times \,\,\frac{2}{5}\) < \(\frac{3}{4}\)

\(\frac{1}{2}\,\, - \,\,\frac{1}{4}\) =  \(\frac{1}{4}\)                                                    \(\frac{3}{4}\,\,:\,\,\frac{6}{9}\,\, - \,\,\frac{1}{2}\) <  \(\frac{7}{8}\)

Giải thích:

- Ta có: \(\frac{4}{5} + \frac{1}{{10}} = \frac{8}{{10}} + \frac{1}{{10}} = \frac{9}{{10}}\); \(\frac{1}{2}\,\, = \,\,\frac{5}{{10}}\)                                                  

\(\frac{9}{{10}}\,\, > \,\,\frac{5}{{10}}\) nên \(\frac{4}{5}\,\, + \,\,\frac{1}{{10}}\) >  \(\frac{1}{2}\)                                                                                                  

- Ta có: \[\frac{5}{8}\,\, \times \,\,\frac{2}{5}\,\, = \,\,\frac{{10}}{{40}}\,\, = \,\,\frac{1}{4}\]

Vì: \[\frac{1}{4} < \frac{3}{4}\] nên \(\frac{5}{8}\,\, \times \,\,\frac{2}{5}\) < \(\frac{3}{4}\)

- Ta có: \[\frac{1}{2}\,\, - \,\,\frac{1}{4}\,\, = \,\,\frac{2}{4}\,\, - \,\,\frac{1}{4}\,\, = \,\,\frac{1}{4}\]                                                         

\[\frac{1}{4} = \frac{1}{4}\] nên \(\frac{1}{2}\,\, - \,\,\frac{1}{4}\) =  \(\frac{1}{4}\)                  

- Ta có: \[\frac{3}{4}\,\,:\,\,\frac{6}{9}\,\, - \,\,\frac{1}{2}\,\, = \,\,\frac{3}{4}\,\, \times \,\,\frac{9}{6}\,\, = \,\,\frac{9}{8}\,\, - \,\,\frac{1}{2}\,\, = \,\,\frac{9}{8}\,\, - \,\,\frac{4}{8}\,\, = \,\,\frac{5}{8}\]

\(\frac{5}{8}\,\, < \,\,\frac{7}{8}\) nên \(\frac{3}{4}\,\,:\,\,\frac{6}{9}\,\, - \,\,\frac{1}{2}\) <  \(\frac{7}{8}\)

CÂU HỎI HOT CÙNG CHỦ ĐỀ

Lời giải

\(\frac{2}{5}\,\, = \,\,\frac{{2\,\, \times \,\,2}}{{5\,\, \times \,\,2}}\,\, = \,\,\frac{4}{{10}}\)

\(\frac{{41}}{{25}}\,\, = \,\,\frac{{41\,\, \times \,\,4}}{{25\,\, \times \,\,4}}\,\, = \,\,\frac{{164}}{{100}}\)

\(\frac{{28}}{{700}}\,\, = \,\,\frac{{28\,\,:\,\,7}}{{700\,\,:\,\,7}}\,\, = \,\,\frac{4}{{100}}\)

\(\frac{{81}}{8}\,\, = \,\,\frac{{81\,\, \times \,\,125}}{{8\,\, \times \,\,125}}\,\, = \,\,\frac{{10{\rm{ }}125}}{{1{\rm{ }}000}}\)

\(\frac{{61}}{{125}}\,\, = \,\,\frac{{61\,\, \times \,\,8}}{{125\,\, \times \,\,8}}\,\, = \,\,\frac{{488}}{{1{\rm{ }}000}}\)

\(\frac{9}{{300}}\,\, = \,\,\frac{{9\,\,:\,\,3}}{{300\,\,:\,\,3}} = \frac{3}{{100}}\)

Lời giải

a) \(\frac{3}{5}\,\, = \,\,\frac{{3\,\, \times \,\,2}}{{5\,\, \times \,\,2}}\,\, = \,\,\frac{6}{{10}}\)                                                            d) \(\frac{{25}}{{500}}\,\, = \,\,\frac{{25\,\,:\,\,5}}{{100\,\,:\,\,5}}\,\, = \,\,\frac{5}{{100}}\)

b) \[\frac{{11}}{{25}}\,\, = \,\,\frac{{11\,\, \times \,\,4}}{{25\,\, \times \,\,4}}\,\, = \,\,\frac{{44}}{{100}}\]                                                      e) \[\frac{{82}}{{2{\rm{ }}000}}\,\, = \,\,\frac{{82\,\,:\,\,2}}{{2{\rm{ }}000\,\,:\,\,2}}\,\, = \,\,\frac{{41}}{{1{\rm{ }}000}}\]

c) \[\frac{3}{4}\,\, = \,\,\frac{{3\,\, \times \,\,25}}{{4\,\, \times \,\,25}}\,\, = \,\,\frac{{75}}{{100}}\]                                                        f) \[\frac{{40}}{{500}}\,\, = \,\,\frac{{40\,\,:\,\,5}}{{500\,\,:\,\,5}}\,\, = \,\,\frac{8}{{100}}\]

Câu 4

A. \(\frac{{35}}{{400}}\)                      
B. \(\frac{{98}}{{300}}\)   
C. \(\frac{{16}}{{70}}\)                                
D. \(\frac{{59}}{{100}}\)

Lời giải

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Câu 5

A. \(\frac{1}{{100}}\)                            
B. \(\frac{{14}}{{19}}\)     
C. \(\frac{{14}}{{10}}\)                                
D. \(\frac{{11}}{{1\,\,000}}\)

Lời giải

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