Tính tích phân của: \[I = \frac{{{e^{3x}} + 1}}{{{e^x} + 1}}\]

A. \[I = \frac{{4({x^2} + 5)}}{{7\sqrt[4]{x}}} + C\]

B. \[I = \frac{{3({x^2} + 7)}}{{7\sqrt[3]{x}}} + C\]

C. \[I = \frac{{3({x^2} + 7)}}{{7\sqrt[4]{x}}} + C\]

D. \[I = \frac{{4({x^2} + 7)}}{{7\sqrt[4]{x}}} + C\]

A. m > 2

B. m≤2

C. m = 2

D. ∀m∈R

A. \[A = \left( {\begin{array}{*{20}{c}}\begin{array}{l}1\\ - 2\\ - 1\end{array}&\begin{array}{l} - 2\\0\\0\end{array}&\begin{array}{l} - 1\\0\\0\end{array}\end{array}} \right)\]

B. \[A = \left( {\begin{array}{*{20}{c}}\begin{array}{l}1\\ - 1\\\frac{{ - 1}}{2}\end{array}&\begin{array}{l} - 1\\0\\0\end{array}&\begin{array}{l}\frac{{ - 1}}{2}\\0\\0\end{array}\end{array}} \right)\]

C. \[A = \left( {\begin{array}{*{20}{c}}\begin{array}{l}\frac{1}{2}\\ - 1\\\frac{{ - 1}}{2}\end{array}&\begin{array}{l} - 1\\0\\0\end{array}&\begin{array}{l}\frac{{ - 1}}{2}\\0\\0\end{array}\end{array}} \right)\]

A. m > 25

B. m≤25

C. m = 25

D. Không có giá trị m

A. 1

B. 2

C. -2

D. -3

A. \[\frac{1}{{\sqrt 2 }}arctg(\frac{{tgx}}{{\sqrt 2 }}) + C\]

B. \[\sqrt 2 arctg(\frac{{tgx}}{{\sqrt 2 }}) + C\]

C. \[ - \sqrt 2 arctg(\frac{{tgx}}{{\sqrt 2 }}) + C\]

D. \[ - \frac{1}{{\sqrt 2 }}arctg(\frac{{tgx}}{{\sqrt 2 }}) + C\]