Tìm \(x,\) biết:

a) \(x + \frac{1}{{ - 5}} = \frac{1}{{10}}.\)

n) \(\left( {2x + \frac{{ - 3}}{4}} \right):\frac{2}{5} = \frac{{ - 10}}{{12}}\)

\[2x + \frac{{ - 3}}{4} = \frac{{ - 10}}{{12}} \cdot \frac{2}{5}\]

\[2x + \frac{{ - 3}}{4} = \frac{{ - 1}}{3}\]

\[2x = \frac{{ - 1}}{3} - \frac{{ - 3}}{4}\]

\[2x = \frac{{ - 1}}{3} + \frac{3}{4}\]

\[2x = \frac{{ - 4}}{{12}} + \frac{9}{{12}}\]

\[2x = \frac{5}{{12}}\]

\[x = \frac{5}{{12}}:2\]

\[x = \frac{5}{{24}}.\]

b) \[x - \frac{4}{5} = \frac{2}{3}\].

\[x = \frac{2}{3} + \frac{4}{5}\]

\[x = \frac{{10}}{{15}} + \frac{{12}}{{15}}\]

\[x = \frac{{22}}{{15}}\]