Tìm \(x,\) biết:

c) \[\frac{{ - 8}}{9} - x = \frac{{ - 11}}{{18}}\].

n) \(\left( {2x + \frac{{ - 3}}{4}} \right):\frac{2}{5} = \frac{{ - 10}}{{12}}\)

\[2x + \frac{{ - 3}}{4} = \frac{{ - 10}}{{12}} \cdot \frac{2}{5}\]

\[2x + \frac{{ - 3}}{4} = \frac{{ - 1}}{3}\]

\[2x = \frac{{ - 1}}{3} - \frac{{ - 3}}{4}\]

\[2x = \frac{{ - 1}}{3} + \frac{3}{4}\]

\[2x = \frac{{ - 4}}{{12}} + \frac{9}{{12}}\]

\[2x = \frac{5}{{12}}\]

\[x = \frac{5}{{12}}:2\]

\[x = \frac{5}{{24}}.\]

i) \[2x - \frac{3}{5} = \frac{4}{7} \cdot \frac{{14}}{6}.\]

\[2x - \frac{3}{5} = \frac{{4 \cdot 14}}{{7 \cdot 6}}\]

\[2x - \frac{3}{5} = \frac{4}{3}\]

\[2x = \frac{3}{5} + \frac{4}{3}\]

\[2x = \frac{9}{{15}} + \frac{{20}}{{15}}\]

\[2x = \frac{{29}}{{15}}\]

\[x = \frac{{29}}{{30}}\]