Cho dãy số $\left({\mathrm{u}}_{\mathrm{n}}\right)$, với ${\mathrm{u}}_{\mathrm{n}}=\frac{3\mathrm{n}-1}{3\mathrm{n}+7}$. Mệnh đề nào dưới đây đúng?

A. $\left\{\begin{array}{l}{\mathrm{u}}_1=6\\ {\mathrm{u}}_{\mathrm{n}}=6{\mathrm{u}}_{\mathrm{n}-1},\mathrm{n}>1\end{array}\right.$

B. $\left\{\begin{array}{l}{\mathrm{u}}_1=6\\ {\mathrm{u}}_{\mathrm{n}}=3{\mathrm{u}}_{\mathrm{n}-1},\mathrm{n}>1\end{array}\right.$

C. $\left\{\begin{array}{l}{\mathrm{u}}_1=3\\ {\mathrm{u}}_{\mathrm{n}}=3{\mathrm{u}}_{\mathrm{n}-1},\mathrm{n}>1\end{array}\right.$

D. $\left\{\begin{array}{l}{\mathrm{u}}_1=3\\ {\mathrm{u}}_{\mathrm{n}}=6{\mathrm{u}}_{\mathrm{n}-1},\mathrm{n}>1\end{array}\right.$

A. ${\mathrm{u}}_{11}=2^{10}.11!$

B. ${\mathrm{u}}_{11}=-2^{10}.11!$

C. ${\mathrm{u}}_{11}=-2^{10}.{11}^{10}$

D. ${\mathrm{u}}_{11}=-2^{10}.{11}^{10}$

A. Dãy số ${\mathrm{u}}_{\mathrm{n}}=\frac{1}{\mathrm{n}}-2$ là dãy tăng

B. Dãy số ${\mathrm{u}}_{\mathrm{n}}={(-1)}^{\mathrm{n}}(2^{\mathrm{n}}+1)$ là dãy giảm.

C. Dãy số ${\mathrm{u}}_{\mathrm{n}}=\frac{\mathrm{n}-1}{\mathrm{n}+1}$ là dãy giảm.

D. Dãy số ${\mathrm{u}}_{\mathrm{n}}=\frac{\mathrm{n}-1}{\mathrm{n}+1}$ là dãy tăng.

A. ${\mathrm{u}}_{\mathrm{n}}=1+\frac{\mathrm{n}(\mathrm{n}+1)(2\mathrm{n}+1)}{6}$

B. ${\mathrm{u}}_{\mathrm{n}}=1+\frac{\mathrm{n}(\mathrm{n}-1)(2\mathrm{n}+2)}{6}$

C. ${\mathrm{u}}_{\mathrm{n}}=1+\frac{\mathrm{n}(\mathrm{n}-1)(2\mathrm{n}-1)}{6}$

D. ${\mathrm{u}}_{\mathrm{n}}=1+\frac{\mathrm{n}(\mathrm{n}+1)(2\mathrm{n}-2)}{6}$

A. 1274,5

B. 2548,5

C. 5096,5

D. 2550,5

A. Dãy $\left({\mathrm{a}}_{\mathrm{n}}\right)$, với ${\mathrm{a}}_{\mathrm{n}}={\left(-\frac{1}{2}\right)}^{\mathrm{n}}$

B. Dãy $\left({\mathrm{b}}_{\mathrm{n}}\right)$, với ${\mathrm{b}}_{\mathrm{n}}=\frac{{\mathrm{n}}^2+1}{\mathrm{n}}$

C. Dãy $\left({\mathrm{c}}_{\mathrm{n}}\right)$, với ${\mathrm{c}}_{\mathrm{n}}=\frac{1}{{\mathrm{n}}^3+1}$

D. Dãy $\left({\mathrm{d}}_{\mathrm{n}}\right)$, với ${\mathrm{d}}_{\mathrm{n}}=3{.2}^{\mathrm{n}}$