Dùng thuốc thử Tollens, đun nóng có thể phân biệt được cặp chất nào sau đây? 

\({{\rm{m}}_{{{\left( {{{\rm{C}}_6}{{\rm{H}}_{10}}{{\rm{O}}_5}} \right)}_{\rm{n}}}}} = 10 \times \frac{{75}}{{100}} = 7,5(\;{\rm{kg}}) \Rightarrow {{\rm{n}}_{{{\left( {{{\rm{C}}_6}{{\rm{H}}_{10}}{{\rm{O}}_5}} \right)}_{\rm{n}}}}} = \frac{{7,5}}{{162{\rm{n}}}}({\rm{kmol}})\)

\({{\rm{n}}_{{{\rm{C}}_2}{{\rm{H}}_5}{\rm{OH}}}} = 2{\rm{n}} \cdot {{\rm{n}}_{{{\left( {{{\rm{C}}_6}{{\rm{H}}_{10}}{{\rm{O}}_5}} \right)}_{\rm{n}}}}} = \frac{{15}}{{162}}({\rm{kmol}}) \Rightarrow {{\rm{m}}_{{{\rm{C}}_2}{{\rm{H}}_5}{\rm{OH}}}} = \frac{{15}}{{162}} \cdot 46 \cdot \frac{{40}}{{100}} = 1,704(\;{\rm{kg}})\)

\( \Rightarrow {{\rm{V}}_{{{\rm{C}}_2}{{\rm{H}}_5}{\rm{OH}}}} = 1,704:0,789 = 2,16(\;{\rm{L}}) \Rightarrow {{\rm{V}}_{{\rm{con }}{{96}^o }}} = 2,16:0,96 \approx 2,25(\;{\rm{L}}).\)

\({{\rm{n}}_{{{\rm{C}}_2}{{\rm{H}}_5}{\rm{OH}}}} = \frac{{100}}{{46}} = 2,174({\rm{kmol}}) \Rightarrow {{\rm{n}}_{{{\left( {{{\rm{C}}_6}{{\rm{H}}_{10}}{{\rm{O}}_5}} \right)}_{\rm{n}}}}} = {{\rm{n}}_{{{\rm{C}}_6}{{\rm{H}}_{22}}{{\rm{O}}_6}}} = \frac{1}{{2{\rm{n}}}}{{\rm{n}}_{{{\rm{C}}_2}{{\rm{H}}_5}{\rm{OH}}}} = \frac{{2,174}}{{2{\rm{n}}}}({\rm{kmol}})\)

\({{\rm{m}}_{{{\left( {{{\rm{C}}_6}{{\rm{H}}_{10}}{{\rm{O}}_5}} \right)}_{\rm{n}}}}} = \frac{{2,174}}{{2{\rm{n}}}} \times 162{\rm{n}} = 176,094(\;{\rm{kg}})\)

\( \Rightarrow {{\rm{m}}_{{\rm{nguyen lieu }}}} = 176,094:0,35:0,5 \approx 1006(\;{\rm{kg}}).\)