Cho điểm \[M\] nằm ngoài mặt cầu \[S\left( {O;R} \right)\]. Khẳng định nào sau đây là đúng?

A. \[{x^2} + {y^2} + {z^2} - 2x = 0.\]

B. \[{x^2} + {y^2} - {z^2} + 2x - y + 1 = 0.\]

C. \[2{x^2} + {y^2} = {\left( {x + y} \right)^2} - {z^2} + 2x + 1.\]

D. \[{\left( {x + y} \right)^2} = 2xy - {z^2} - 1.\]

A. \[{x^2} + {y^2} + {z^2} + 4x - 2y + 2z = 0.\]

B. \[{x^2} + {y^2} + {z^2} - 4x - 2y + 2z = 0.\]

C. \[{x^2} + {y^2} + {z^2} - 2x - y + z - 6 = 0.\]

D. \[{x^2} + {y^2} + {z^2} - 4x - 2y + 2z + 6 = 0.\]

A. \[{\left( {x - 1} \right)^2} + {\left( {y - 2} \right)^2} + {\left( {z - 3} \right)^2} = \frac{{\sqrt {213} }}{3}.\]

B. \[{\left( {x - 1} \right)^2} + {\left( {y - 2} \right)^2} + {\left( {z - 3} \right)^2} = \frac{{71}}{3}.\]

C. \[{\left( {x + 1} \right)^2} + {\left( {y + 2} \right)^2} + {\left( {z + 3} \right)^2} = \frac{{\sqrt {213} }}{3}.\]

D. \[{\left( {x + 1} \right)^2} + {\left( {y + 2} \right)^2} + {\left( {z + 3} \right)^2} = \frac{{71}}{3}.\]

A. \[\left( {9;18; - 27} \right).\]

B. \[\left( { - 3; - 6;9} \right).\]

C. \[\left( {3;6; - 9} \right).\]

D. \[\left( { - 9; - 18;27} \right).\]

A. \[{\left( {x - {x_0}} \right)^2} + {\left( {y - {y_0}} \right)^2} + {\left( {z - {z_0}} \right)^2} = {R^2}.\]

B. \[\left( {x - {x_0}} \right) + \left( {y - {y_0}} \right) + \left( {z - {z_0}} \right) = R.\]

C. \[\left( {x - {x_0}} \right) + \left( {y - {y_0}} \right) + \left( {z - {z_0}} \right) = {R^2}.\]

D. \[{\left( {x - {x_0}} \right)^2} - {\left( {y - {y_0}} \right)^2} - {\left( {z - {z_0}} \right)^2} = {R^2}.\]

A. \[{x^2} + {y^2} + {z^2} + 2x + 2y - 2z + 4 = 0.\]

B. \[{x^2} + {y^2} + {z^2} + 4x - 2y + 2z + 6 = 0.\]

C. \[{x^2} + {y^2} + {z^2} + 2x - 6y + 4z + 14 = 0.\]

D. \[{x^2} + {y^2} + {z^2} + 8x - 6y + 2z - 10 = 0.\]

A. 7.

B. 9.

C. 8.

D. 6.