C. Nếu \(\int\limits_1^2 {f\left( x \right){\mkern 1mu} } {\rm{d}}x = 2\) và \(\int\limits_1^2 {g\left( x \right){\mkern 1mu} } {\rm{d}}x = 6\) thì \(\int\limits_2^1 {\left[ {f\left( x \right) - g\left( x \right)} \right]{\mkern 1mu} } {\rm{d}}x =  - 4\)

A. Nếu \[\int\limits_0^1 {f(x)} dx =  - 1\] và \[\int\limits_0^3 {f(x)} dx = 5\] thì \[\int\limits_1^3 {f(x)}  = 6\]dx

A. Biết \[\int\limits_1^2 {f\left( x \right)dx}  = 2\]. Giá trị của \[\int\limits_2^1 {3f\left( x \right)dx}  =  - 6\].

A. Nếu \(\int\limits_{ - 1}^5 {f\left( x \right)} {\rm{d}}x =  - 3\) thì \(\int\limits_5^{ - 1} {f\left( x \right)\,} {\rm{d}}x = 3\)

C. Nếu \(\mathop \smallint \limits_{ - 1}^0 f\left( x \right)dx = 3;\mathop \smallint \limits_0^3 f\left( x \right)dx = 3\) thì \(\mathop \smallint \limits_1^3 f\left( x \right)dx =  - 4\)

D. Nếu \(\int\limits_{ - 2}^5 {f\left( x \right){\rm{d}}} x = 8\) và \(\int\limits_5^{ - 2} {g\left( x \right){\rm{d}}} x = 3\) thì \(\int\limits_{ - 2}^5 {\left[ {f\left( x \right) - 4g\left( x \right) - 1} \right]{\rm{d}}} x =  - 13\)

D. Nếu \(\int\limits_0^2 {\left( {f\left( x \right) + 3{x^2}} \right){\rm{d}}x}  = 10\) thì \(\int\limits_0^2 {f\left( x \right){\rm{d}}x}  = 2\).