Phiếu bài tập hàng ngày Toán lớp 5 Bài 6. Cộng, trừ hai phân số khác mẫu số (có đáp án)

a) \(\frac{3}{4}\,\, + \,\,\frac{8}{9}\,\, = \,\,\frac{{12}}{{36}}\,\, + \,\,\frac{{72}}{{36}}\,\, = \,\,\frac{{84}}{{36}}\,\, = \,\,\frac{7}{3}\)   

Giải thích:

\(\frac{3}{4}\,\, + \,\,\frac{8}{9}\,\, = \,\,\frac{{27}}{{36}}\,\, + \,\,\frac{{32}}{{36}}\,\, = \,\,\frac{{59}}{{36}}\,\,\)

c) \(7\,\, - \,\,\frac{1}{{12}}\,\, = \,\,\frac{7}{{12}}\,\, - \,\,\frac{1}{{12}}\,\, = \,\,\frac{6}{{12}}\,\, = \,\,\frac{1}{2}\)   

Giải thích:

\(7\,\, - \,\,\frac{1}{{12}}\,\, = \,\,\frac{{84}}{{12}}\,\, - \,\,\frac{1}{{12}}\,\, = \,\,\frac{{83}}{{12}}\,\,\)

b)\(\frac{5}{8}\,\, - \,\,\frac{3}{5}\,\, = \,\,\frac{{25}}{{40}}\,\, - \,\,\frac{{24}}{{40}}\,\, = \,\,\frac{1}{{40}}\)           

d) \(\frac{{12}}{7}\,\, + \,\,3\,\, = \,\,\frac{{12}}{7}\,\, + \,\,\frac{{21}}{7}\,\, = \,\,\frac{{33}}{7}\)   

a) \(\frac{3}{4}\,\, + \,\,\frac{1}{5}\)

\(\begin{array}{l} = \frac{{15}}{{20}} + \frac{4}{{20}}\\ = \frac{{19}}{{20}}\end{array}\)

b) \(\frac{{13}}{6}\,\, + \,\,\frac{{11}}{{15}}\)

\(\begin{array}{l} = \frac{{130}}{{60}} + \frac{{44}}{{60}}\\ = \frac{{174}}{{60}}\end{array}\)

c) \(\frac{{27}}{7}\,\, + \,\,\frac{1}{{21}}\)

 \(\begin{array}{l} = \frac{{81}}{{21}} + \frac{1}{{21}}\\ = \frac{{82}}{{21}}\end{array}\)

d) \(\frac{8}{9}\,\, - \,\,\frac{5}{6}\)

\( = \,\,\frac{{16}}{{18}}\,\, - \,\,\frac{{15}}{{18}}\)

\( = \,\,\frac{1}{{18}}\)

e) \(\frac{{18}}{{11}}\,\, - \,\,\frac{{15}}{{22}}\)

\(\begin{array}{l} = \frac{{36}}{{22}} - \frac{{15}}{{22}}\\ = \frac{{21}}{{22}}\end{array}\)

f) \[\frac{{11}}{7}\,\, - \,\,\frac{5}{8}\]

\[\begin{array}{l} = \frac{{88}}{{56}} - \frac{{35}}{{56}}\\ = \frac{{53}}{{36}}\end{array}\]