Đề thi giữa kì 1 Toán 10 năm 2023-2024 THPT Ngô Thì Nhậm (Hà Nội) có đáp án

A. \[\frac{a}{{\sin A}} = \frac{b}{{\sin C}}\,.\]

B. \[\frac{a}{{\sin A}} = \frac{b}{{\sin B}}\,.\]

C. \[\frac{a}{{\sin A}} = \frac{c}{{\sin C}}\,.\]

D. \[\frac{a}{{\sin A}} = 2R\,.\]

A. \[x = 2023\].

B. \[x = - 23\].

C. \[x = 2\].

D. \[x = 0\].

120.

110.

100.

96.

A. \[{b^2} = {a^2} + {c^2} - 2ac\cos A\].

B. \[{b^2} = {a^2} + {c^2} - 2ac\cos B\].

C. \[{b^2} = {a^2} + {c^2} + 2ac\cos B\].

D. \[{b^2} = {a^2} + {c^2} - ac\cos B\].

A. \(S = \frac{1}{2}ac\cos B\,.\)

B. \(S = \frac{1}{2}ac\sin B\,.\)

C. \(S = \frac{1}{2}ac\sin A\,.\)

D. \(S = \frac{1}{2}bc\cos A\,.\)

\(\tan \left( {{{180}^{\rm{o}}} - \alpha } \right) = \tan \alpha \).

\(\tan \left( {{{180}^{\rm{o}}} - \alpha } \right) = - \tan \alpha \).

\(\tan \left( {{{180}^{\rm{o}}} - \alpha } \right) = \cot \alpha \).

\(\tan \left( {{{180}^{\rm{o}}} - \alpha } \right) = - \cot \alpha \).

A. \(\frac{{\sqrt 2 }}{2}\).

B. \(2\sqrt 2 \).

C. 1.

D. \(\sqrt 2 \).

A. \[A \cup B = \left\{ { - 1;0} \right\}\].

B. \[A \cup B = \left\{ { - 1;0;1;2;3;6;9} \right\}\].

C. \[A \cup B = \left\{ {1;2} \right\}\].

D. \[A \cup B = \left\{ {3;6;9} \right\}\].

A. \(\left( {3;1} \right)\).

B. \(\left( { - 3; - 1} \right)\).

C. \(\left( { - 1;4} \right)\).

D. \(\left( {9; - 1} \right)\).

A. 3.

B. 8.

C. 5.

D. 6.

A. \[\left\{ \begin{array}{l}x - 2y > 0\\x + 3y + 2 > 0\end{array} \right.\].

B. \[\left\{ \begin{array}{l}x - 2y < 0\\x + 3y + 2 < 0\end{array} \right.\].

C. \[\left\{ \begin{array}{l}x - 2y > 0\\x + 3y + 2 < 0\end{array} \right.\].

A. \(\left\{ \begin{array}{l}x + y > 0\\x - \frac{3}{y} \le 2\end{array} \right.\).

B. \(\left\{ \begin{array}{l}x - y < 7\\2x + y = 3\end{array} \right.\).

C. \(\left\{ \begin{array}{l}x + y > 0\\{2^2}x - 3y \le 1\end{array} \right.\).

A. \(x + 3y - 6 \le 0\).

B. \(2x - y + 5 > 0\).

C. \(2x + 3y - 6 \ge 0\).

D. \(3x + 2y - 7 \le 0\).

\[A \cap B = \{ x|x \notin A\]và \[x \in B\} .\]

\[A \cap B = \{ x|x \in A\]và \[x \in B\} .\]

\[A \cap B = \{ x|x \in A\]và \[x \notin B\} .\]

\[A \cap B = \{ x|x \in A\]hoặc \[x \in B\} .\]

A. \(x - 3{y^2} \ge 0\).

B. \((x - 1)(y + 3) < x + 2\).

C. \(2x + 3y \ge 4\).

A. \(A = \left\{ { - 1;0;1;2;3} \right\}\).

B. \(A = \left\{ {0;1;2;3} \right\}\).

C. \(A = \left\{ {0;1;2;3;4} \right\}\).

D. \(A = \left\{ { - 1;0;1;2;3;4} \right\}\).

\(\left\{ x \right\}\).

\(\emptyset \).

\(\left\{ {a;b;c} \right\}\).

\(\left\{ {2\,;\,3\,} \right\}\).

\(\forall x \in \mathbb{R}:{x^2} \ge 0\).

\(\exists x \in \mathbb{R}:{x^2} \ge 0\).

\(\exists x \in \mathbb{R}:{x^2} \le 0\).

\(\forall x \in \mathbb{R}:{x^2} \le 0\).