Trong không gian Oxyz, cho hình bình hành ABCD với  A(0,1,1), B(−2,3,1) và C(4,−3,1). Phương trình nào không phải là phương trình tham số của đường chéo BD.

A.\(\left\{ {\begin{array}{*{20}{c}}{x = 6t}\\{y = - 4t}\\{z = - 3t}\end{array}} \right.\)

B. \(\left\{ {\begin{array}{*{20}{c}}{x = 6t}\\{y = 2 + 4t}\\{z = - 3t}\end{array}} \right.\)

C. \(\left\{ {\begin{array}{*{20}{c}}{x = 6t}\\{y = 4t}\\{z = - 3t}\end{array}} \right.\)

D. \(\left\{ {\begin{array}{*{20}{c}}{x = 6t}\\{y = 4t}\\{z = 1 - 3t}\end{array}} \right.\)

A.(0;1;2)           

B.(1;0;1)

C.(2;−2;1)        

D.(3;−4;1) 

A.\[\frac{x}{2} = \frac{y}{{ - 1}} = \frac{z}{1}\]

B. \[\frac{x}{2} = \frac{y}{1} = \frac{z}{1}\]

C. \[\frac{x}{2} = \frac{y}{{ - 1}} = \frac{z}{{ - 1}}\]

D. \[\frac{x}{{ - 2}} = \frac{y}{1} = \frac{z}{1}\]

A.\[\frac{{x + 1}}{2} = \frac{{y + 2}}{{ - 3}} = \frac{{z - 3}}{4}\]

B. \[\frac{{x - 1}}{3} = \frac{{y - 2}}{{ - 1}} = \frac{{z + 3}}{1}\]

C. \[\frac{{x - 3}}{1} = \frac{{y + 1}}{2} = \frac{{z - 1}}{{ - 3}}\]

D. \[\frac{{x - 1}}{2} = \frac{{y - 2}}{{ - 3}} = \frac{{z + 3}}{4}\]

A.\[d:\frac{{x - 1}}{4} = \frac{{y - 2}}{{ - 7}} = \frac{{z - 3}}{{ - 1}}\]

B. \[d:\frac{{x - 1}}{4} = \frac{{y - 2}}{7} = \frac{{z - 3}}{1}\]

C. \[d:\frac{{x - 1}}{{ - 4}} = \frac{{y - 2}}{{ - 7}} = \frac{{z - 3}}{1}\]

D. \[d:\frac{{x - 1}}{4} = \frac{{y - 2}}{{ - 7}} = \frac{{z - 3}}{1}\]

A.(−1;−1;1)     

B.(−1;1;1)        

C.(0;1;1)

D.(0;1;0)

A.\(\Delta :\left\{ {\begin{array}{*{20}{c}}{x = 1 - 4t}\\{y = 2 + 3t}\\{z = - 1 - 2t}\end{array}} \right.\)

B. \(\Delta :\left\{ {\begin{array}{*{20}{c}}{x = - 4 + t}\\{y = 3 + 2t}\\{z = - 2 - t}\end{array}} \right.\)

C. \(\Delta :\left\{ {\begin{array}{*{20}{c}}{x = 4 + t}\\{y = - 3 + 2t}\\{z = 2 - t}\end{array}} \right.\)

D. \(\Delta :\left\{ {\begin{array}{*{20}{c}}{x = 1 + 4t}\\{y = 2 - 3t}\\{z = - 1 + 2t}\end{array}} \right.\)