ĐGNL ĐHQG Hà Nội - Tư duy định lượng - Phương trình đường elip

A.${c^2} = {a^2} + {b^2}$

b. ${b^2} = {a^2} + {c^2}$

C. ${a^2} = {b^2} + {c^2}$

D. $c = a + b$

A.c

B.c

C.c>b>a.

D.c

A.$2a = {F_1}{F_2}$

B. $2a >{F_1}{F_2}$

C. $2a < {F_1}{F_2}$

D. $4a = {F_1}{F_2}$

A.$\frac{1}{{\sqrt 2 }}$

B. $\frac{2}{{\sqrt 2 }}$

C. $\frac{1}{3}$

D. 1

A.1 và 2

B.2 và 3

C.1 và 3

D.4 và 1

A.$\frac{{{x^2}}}{{36}} + \frac{{{y^2}}}{{16}} = 1$

B. $\frac{{{x^2}}}{{144}} + \frac{{{y^2}}}{{64}} = 1$

C. $\frac{{{x^2}}}{{12}} + \frac{{{y^2}}}{8} = 1$

D. $\frac{{{x^2}}}{{16}} + \frac{{{y^2}}}{{36}} = 1$

A.$\frac{{{x^2}}}{{100}} + \frac{{{y^2}}}{{36}} = 1$

B. $\frac{{{x^2}}}{{100}} + \frac{{{y^2}}}{{64}} = 1$

C. $\frac{{{x^2}}}{{400}} + \frac{{{y^2}}}{{256}} = 1$

D. $\frac{{{x^2}}}{{100}} + \frac{{{y^2}}}{{49}} = 1$

A.$\frac{{{x^2}}}{{100}} + \frac{{{y^2}}}{{16}} = 1$

B. $\frac{{{x^2}}}{{64}} + \frac{{{y^2}}}{{25}} = 1$

C. $\frac{{{x^2}}}{{100}} + \frac{{{y^2}}}{{64}} = 1$

D. $\frac{{{x^2}}}{{25}} + \frac{{{y^2}}}{{16}} = 1$

A.$\frac{{{x^2}}}{5} + \frac{{{y^2}}}{3} = 1$

B. $\frac{{{x^2}}}{{100}} + \frac{{{y^2}}}{{36}} = 1$

C. $\frac{{{x^2}}}{{25}} + \frac{{{y^2}}}{9} = 1$

D. $\frac{{{x^2}}}{{10}} + \frac{{{y^2}}}{6} = 1$

A.$\frac{{{x^2}}}{{25}} + \frac{{{y^2}}}{{16}} = 1$

B. $\frac{{{x^2}}}{5} + \frac{{{y^2}}}{4} = 1$

C. $\frac{{{x^2}}}{{25}} + \frac{{{y^2}}}{9} = 1$

D. $\frac{x}{5} + \frac{y}{4} = 1$

A.$\frac{{{x^2}}}{{24}} + \frac{{{y^2}}}{{25}} = 1$

B. $\frac{{{x^2}}}{{24}} + \frac{{{y^2}}}{{25}} = - 1$

C. $\frac{{{x^2}}}{{25}} + \frac{{{y^2}}}{{24}} = 1$

D. $\frac{{{x^2}}}{{25}} + \frac{{{y^2}}}{{24}} = - 1$Trả lời:

A.$\frac{{{x^2}}}{7} + \frac{{{y^2}}}{2} = 1$

B.$\frac{{{x^2}}}{{20}} + \frac{{{y^2}}}{4} = 1$

C. $\frac{{{x^2}}}{4} + \frac{{{y^2}}}{1} = 1$

D. $\frac{{{x^2}}}{9} + \frac{{{y^2}}}{4} = 1$

A.$\frac{{{x^2}}}{{16}} + \frac{{{y^2}}}{9} = 1$

B. $\frac{{{x^2}}}{{25}} + \frac{{{y^2}}}{9} = 1$

C. $\frac{{{x^2}}}{{25}} + \frac{{{y^2}}}{{16}} = 1$

D. $\frac{{{x^2}}}{{36}} + \frac{{{y^2}}}{{16}} = 1$

A.$\frac{{{x^2}}}{4} + \frac{{{y^2}}}{1} = 1$

B. $\frac{{{x^2}}}{4} + \frac{{{y^2}}}{2} = 1$

C. $\frac{{{x^2}}}{9} + \frac{{{y^2}}}{4} = 1$

D. $\frac{{{x^2}}}{9} + \frac{{{y^2}}}{1} = 1$

A.$\frac{{{x^2}}}{4} + \frac{{{y^2}}}{1} = 1$

B. $\frac{{{x^2}}}{9} + \frac{{{y^2}}}{4} = 1$

C. $\frac{{{x^2}}}{9} + \frac{{{y^2}}}{1} = 1$

D. $\frac{{{x^2}}}{{16}} + \frac{{{y^2}}}{9} = 1$Trả lời:

A.${y_M} \in \left( {0;\sqrt 3 } \right)$

B. ${y_M} \in \left( {2;\sqrt 8 } \right)$

C. ${y_M} \in \left( {\sqrt 8 ;5} \right)$

D. ${y_M} \in \left( {\sqrt 3 ;2} \right)$