ĐGNL ĐHQG Hà Nội - Tư duy định lượng - Phương trình đường elip

A.\[{c^2} = {a^2} + {b^2}\]

b. \[{b^2} = {a^2} + {c^2}\]

C. \[{a^2} = {b^2} + {c^2}\]

D. \[c = a + b\]

A.c

B.c

C.c>b>a.

D.c

A.\[2a = {F_1}{F_2}\]

B. \[2a >{F_1}{F_2}\]

C. \[2a < {F_1}{F_2}\]

D. \[4a = {F_1}{F_2}\]

A.\[\frac{1}{{\sqrt 2 }}\]

B. \[\frac{2}{{\sqrt 2 }}\]

C. \[\frac{1}{3}\]

D. 1

A.1 và 2

B.2 và 3

C.1 và 3

D.4 và 1

A.\[\frac{{{x^2}}}{{36}} + \frac{{{y^2}}}{{16}} = 1\]

B. \[\frac{{{x^2}}}{{144}} + \frac{{{y^2}}}{{64}} = 1\]

C. \[\frac{{{x^2}}}{{12}} + \frac{{{y^2}}}{8} = 1\]

D. \[\frac{{{x^2}}}{{16}} + \frac{{{y^2}}}{{36}} = 1\]

A.\[\frac{{{x^2}}}{{100}} + \frac{{{y^2}}}{{36}} = 1\]

B. \[\frac{{{x^2}}}{{100}} + \frac{{{y^2}}}{{64}} = 1\]

C. \[\frac{{{x^2}}}{{400}} + \frac{{{y^2}}}{{256}} = 1\]

D. \[\frac{{{x^2}}}{{100}} + \frac{{{y^2}}}{{49}} = 1\]

A.\[\frac{{{x^2}}}{{100}} + \frac{{{y^2}}}{{16}} = 1\]

B. \[\frac{{{x^2}}}{{64}} + \frac{{{y^2}}}{{25}} = 1\]

C. \[\frac{{{x^2}}}{{100}} + \frac{{{y^2}}}{{64}} = 1\]

D. \[\frac{{{x^2}}}{{25}} + \frac{{{y^2}}}{{16}} = 1\]

A.\[\frac{{{x^2}}}{5} + \frac{{{y^2}}}{3} = 1\]

B. \[\frac{{{x^2}}}{{100}} + \frac{{{y^2}}}{{36}} = 1\]

C. \[\frac{{{x^2}}}{{25}} + \frac{{{y^2}}}{9} = 1\]

D. \[\frac{{{x^2}}}{{10}} + \frac{{{y^2}}}{6} = 1\]

A.\[\frac{{{x^2}}}{{25}} + \frac{{{y^2}}}{{16}} = 1\]

B. \[\frac{{{x^2}}}{5} + \frac{{{y^2}}}{4} = 1\]

C. \[\frac{{{x^2}}}{{25}} + \frac{{{y^2}}}{9} = 1\]

D. \[\frac{x}{5} + \frac{y}{4} = 1\]

A.\[\frac{{{x^2}}}{{24}} + \frac{{{y^2}}}{{25}} = 1\]

B. \[\frac{{{x^2}}}{{24}} + \frac{{{y^2}}}{{25}} = - 1\]

C. \[\frac{{{x^2}}}{{25}} + \frac{{{y^2}}}{{24}} = 1\]

D. \[\frac{{{x^2}}}{{25}} + \frac{{{y^2}}}{{24}} = - 1\]Trả lời:

A.\[\frac{{{x^2}}}{7} + \frac{{{y^2}}}{2} = 1\]

B.\[\frac{{{x^2}}}{{20}} + \frac{{{y^2}}}{4} = 1\]

C. \[\frac{{{x^2}}}{4} + \frac{{{y^2}}}{1} = 1\]

D. \[\frac{{{x^2}}}{9} + \frac{{{y^2}}}{4} = 1\]

A.\[\frac{{{x^2}}}{{16}} + \frac{{{y^2}}}{9} = 1\]

B. \[\frac{{{x^2}}}{{25}} + \frac{{{y^2}}}{9} = 1\]

C. \[\frac{{{x^2}}}{{25}} + \frac{{{y^2}}}{{16}} = 1\]

D. \[\frac{{{x^2}}}{{36}} + \frac{{{y^2}}}{{16}} = 1\]

A.\[\frac{{{x^2}}}{4} + \frac{{{y^2}}}{1} = 1\]

B. \[\frac{{{x^2}}}{4} + \frac{{{y^2}}}{2} = 1\]

C. \[\frac{{{x^2}}}{9} + \frac{{{y^2}}}{4} = 1\]

D. \[\frac{{{x^2}}}{9} + \frac{{{y^2}}}{1} = 1\]

A.\[\frac{{{x^2}}}{4} + \frac{{{y^2}}}{1} = 1\]

B. \[\frac{{{x^2}}}{9} + \frac{{{y^2}}}{4} = 1\]

C. \[\frac{{{x^2}}}{9} + \frac{{{y^2}}}{1} = 1\]

D. \[\frac{{{x^2}}}{{16}} + \frac{{{y^2}}}{9} = 1\]Trả lời:

A.\[{y_M} \in \left( {0;\sqrt 3 } \right)\]

B. \[{y_M} \in \left( {2;\sqrt 8 } \right)\]

C. \[{y_M} \in \left( {\sqrt 8 ;5} \right)\]

D. \[{y_M} \in \left( {\sqrt 3 ;2} \right)\]