Bộ 10 đề thi cuối kì 1 Toán 11 Cánh diều có đáp án - Đề 4

\(\frac{5}{8}\pi .\)

\(\frac{8}{5}\pi .\)

\(\frac{5}{3}\pi .\)

\(\frac{3}{5}\pi .\)

\(\frac{1}{3}\).

\( - \frac{1}{3}\).

\( - \frac{2}{3}\).

\(\frac{2}{3}\).

\(P = \frac{{11}}{{100}}.\)

\(P = - \frac{{11}}{{100}}.\)

\(P = \frac{7}{{25}}.\)

\(P = \frac{{10}}{{11}}.\)

\(y = \sin 2x.\)

\(y = \cos x.\)

\(y = \tan 3x.\)

\(y = 2\cot x.\)

\(m = - 2023\sqrt 2 .\)

\(m = - \sqrt 2 .\)

\(m = - 2024\sqrt 2 .\)

\(m = - 1.\)

\(m > 1.\)

\(m < - 1.\)

\[\left[ \begin{array}{l}x = \frac{\pi }{4} + k2\pi \\x = \frac{{3\pi }}{4} + k2\pi \end{array} \right.\,\,\left( {k \in \mathbb{Z}} \right)\].

\[\left[ \begin{array}{l}x = \frac{{3\pi }}{4} + k2\pi \\x = \frac{{ - 3\pi }}{4} + k2\pi \end{array} \right.\,\,\left( {k \in \mathbb{Z}} \right)\].

\[\left[ \begin{array}{l}x = \frac{{5\pi }}{4} + k2\pi \\x = \frac{{ - 5\pi }}{4} + k2\pi \end{array} \right.\,\,\left( {k \in \mathbb{Z}} \right)\].

\[\left[ \begin{array}{l}{\rm{x}} = \frac{\pi }{4} + k2\pi \\x = \frac{{ - \pi }}{4} + k2\pi \end{array} \right.\,\,\left( {k \in \mathbb{Z}} \right)\].

\[\left\{ {\frac{\pi }{3};\,\,\frac{\pi }{3};\,\,\frac{\pi }{3}} \right\},\,\,\left\{ {\frac{\pi }{4};\,\,\frac{\pi }{4};\,\,\frac{\pi }{2}} \right\}.\]

\[\left\{ {\frac{\pi }{3};\,\,\frac{\pi }{3};\,\,\frac{\pi }{3}} \right\},\,\,\left\{ {\frac{{2\pi }}{3};\,\,\frac{\pi }{6};\,\,\frac{\pi }{6}} \right\}.\]

\[\left\{ {\frac{{2\pi }}{3};\,\,\frac{\pi }{6};\,\,\frac{\pi }{6}} \right\}.\]

\[\left\{ {\frac{\pi }{3};\,\,\frac{\pi }{3};\,\,\frac{\pi }{3}} \right\}.\]

16.

20.

22.

24.

\[{u_n} = \sqrt {{n^2} + 1} \].

\[{u_n} = n + \frac{1}{n}\].

\[{u_n} = {2^n} + 1\].

\[{u_n} = \frac{n}{{n + 1}}\].

\({u_n} = {u_{n - 1}} - d,\,\,\left( {n \ge 2} \right).\)

\({u_n} = {u_{n - 1}} + d,\,\,\left( {n \ge 2} \right).\)

\({u_n} = {u_{n - 1}} \cdot d,\,\,\left( {n \ge 2} \right).\)

\({u_n} = {u_{n - 1}} + 2d,\,\,\left( {n \ge 2} \right).\)

\({u_1} = 16.\)

\({u_1} = - 16.{\mkern 1mu} \;\;\;\;\)

\({u_1} = \frac{1}{{16}}.{\mkern 1mu} \)

\({u_1} = - \frac{1}{{16}}.\;\;\;\)

\(1;\,\,\,1\,\,;\,\,1;\,\,1;...\)

\(2;\,\,4;\,\,8;\,\,16;...\)

\(\sqrt 2 ;\,\,2;\,\,2\sqrt 2 ;\,\,4\sqrt 2 ;...\)

\(1;\,\, - \frac{1}{3};\,\,\frac{1}{9};\,\, - \frac{1}{{27}};...\)

720.

81.

64.

56.

\(a - b\).

\(a + b\).

\(a \cdot b\).

\({a^b}\).

\( + \infty \).

\(\frac{1}{2}\).

\(1\).

\(2\).

6.

2.

5.

\(\frac{3}{2}.\)

\( - \infty \).

\(2\).

\(1\).

\( + \infty \).

\(f\left( x \right) = \frac{{2{x^2} + 6x + 1}}{{x + 2}}\).

\(f\left( x \right) = \frac{{x + 1}}{{x - 2}}\).

\(f\left( x \right) = \frac{{{x^2} + x + 1}}{{x - 2}}\).

\(f\left( x \right) = \frac{{3{x^2} - x - 2}}{{{x^2} - 4}}\).